fsck: provide a function to fsck buffer without object struct

The fsck code has been slowly moving away from requiring an object
struct in commits like 103fb6d43b (fsck: accept an oid instead of a
"struct tag" for fsck_tag(), 2019-10-18), c5b4269b57 (fsck: accept an
oid instead of a "struct commit" for fsck_commit(), 2019-10-18), etc.

However, the only external interface that fsck.c provides is
fsck_object(), which requires an object struct, then promptly discards
everything except its oid and type. Let's factor out the post-discard
part of that function as fsck_buffer(), leaving fsck_object() as a thin
wrapper around it. That will provide more flexibility for callers which
may not have a struct.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 8 insertions, 0 deletions

diff --git a/fsck.h b/fsck.h
index fcecf4101c..668330880e 100644
--- a/fsck.h
+++ b/fsck.h
@@ -184,6 +184,14 @@ int fsck_object(struct object *obj, void *data, unsigned long size,
 	struct fsck_options *options);
 
 /*
+ * Same as fsck_object(), but for when the caller doesn't have an object
+ * struct.
+ */
+int fsck_buffer(const struct object_id *oid, enum object_type,
+		void *data, unsigned long size,
+		struct fsck_options *options);
+
+/*
  * fsck a tag, and pass info about it back to the caller. This is
  * exposed fsck_object() internals for git-mktag(1).
  */